Uncover the Power of hasSuffix() in Swift

When working with strings in Swift, understanding the intricacies of the hasSuffix() method is crucial. This powerful tool allows developers to effortlessly determine whether a string ends with a specified substring or not.

* Syntax Unraveled *

The syntax of the hasSuffix() method is straightforward: string.hasSuffix(str). Here, string is an object of the String class, and str is the substring to be checked.

* Parameters Decoded *

The hasSuffix() method takes a single parameter: str. This parameter specifies the substring to be checked against the original string.

* Return Value Revealed *

The hasSuffix() method returns a boolean value indicating whether the string ends with the given substring or not. If the string ends with the specified substring, it returns true; otherwise, it returns false.

* Case-Sensitivity Alert *

It’s essential to note that the hasSuffix() method is case-sensitive. This means that the method treats uppercase and lowercase characters differently.

* Real-World Examples *

Let’s explore two examples to demonstrate the hasSuffix() method in action:

Example 1: Swift String hasSuffix()
In this example, we’ll check if the string “hello world” ends with the substring “world”.

swift
let str = "hello world"
if str.hasSuffix("world") {
print("The string ends with 'world'.")
} else {
print("The string doesn't end with 'world'.")
}

Example 2: Using hasSuffix() with if…else
In this example, we’ll use the hasSuffix() method with an if...else statement to check if a string ends with a specific suffix.

swift
let filename = "example.txt"
if filename.hasSuffix(".txt") {
print("The file is a text file.")
} else {
print("The file is not a text file.")
}

By mastering the hasSuffix() method, you’ll be able to tackle complex string manipulation tasks with ease and precision.

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