Unlock the Secrets of Leap Years in C Programming

Are you ready to dive into the world of C programming and discover the intricacies of leap years? Let’s embark on a journey to create a program that can accurately identify these unique years.

The Rules of Leap Years

To start, it’s essential to understand the fundamental rules that govern leap years. A leap year is precisely divisible by 4, except for century years (those ending with 00). However, there’s a catch – a century year is only considered a leap year if it’s perfectly divisible by 400. This means that 1999 is not a leap year, while 2000 and 2004 are.

Crafting the Perfect Program

Now that we’ve grasped the rules, let’s create a C program that can check whether a given year is a leap year or not. Our program will utilize the if...else statement, a crucial element in C programming, to evaluate the input year.

“`c

include

int main() {
int year;
printf(“Enter a year: “);
scanf(“%d”, &year);

if (year % 4 == 0) {
    if (year % 100 == 0) {
        if (year % 400 == 0)
            printf("%d is a leap year\n", year);
        else
            printf("%d is not a leap year\n", year);
    } else
        printf("%d is a leap year\n", year);
} else
    printf("%d is not a leap year\n", year);

return 0;

}
“`

Testing Our Program

Let’s put our program to the test! We’ll run it with two different inputs to see how it performs.

Output 1
Enter a year: 1999
1999 is not a leap year

Output 2
Enter a year: 2000
2000 is a leap year

With our program, we can confidently determine whether a given year is a leap year or not. By mastering this concept, you’ll be well on your way to becoming a proficient C programmer.