Reverse Numbers with Ease: A Step-by-Step Guide

The Art of Reversing Numbers: Unraveling the Mystery

Reversing numbers may seem like a daunting task, but fear not! With a simple program, you can unlock the secrets of this mathematical puzzle.

Step-by-Step Breakdown

Let’s dive into the world of number reversal using a Kotlin program. The magic happens when we utilize a while loop to extract each digit of the original number.

Digit Extraction

First, we store the remainder of the number divided by 10 in a variable called digit. This clever trick allows us to isolate the last digit of the number, which in our example is 4.

Building the Reversed Number

Next, we add digit to the reversed variable after multiplying it by 10. This multiplication has a profound effect: it adds a new place value to the reversed number. Think of it like shifting the decimal point one position to the left.

Iterative Process

The program then iterates through the following steps:

• num is divided by 10, leaving us with the remaining digits: 123.
• In the second iteration, digit equals 3, reversed becomes 4 * 10 + 3 = 43, and num is reduced to 12.
• The third iteration yields digit equal to 2, reversed becomes 43 * 10 + 2 = 432, and num dwindles to 1.
• The final iteration results in digit equal to 1, reversed becomes 432 * 10 + 1 = 4321, and num reaches 0.

The Grand Finale

When num finally reaches 0, the while loop exits, and the reversed variable proudly holds the reversed number: 4321.

Java Counterpart

Curious about the Java equivalent? Here’s the Java program to reverse a number, showcasing the same logic and principles:

[Insert Java code]

Now, go ahead and try reversing numbers like a pro!