The Art of Reversing Numbers: Unraveling the Mystery

Reversing numbers may seem like a daunting task, but fear not! With a simple program, you can unlock the secrets of this mathematical puzzle.

Step-by-Step Breakdown

Let’s dive into the world of number reversal using a Kotlin program. The magic happens when we utilize a while loop to extract each digit of the original number.

Digit Extraction

First, we store the remainder of the number divided by 10 in a variable called digit. This clever trick allows us to isolate the last digit of the number, which in our example is 4.

var digit = num % 10

Building the Reversed Number

Next, we add digit to the reversed variable after multiplying it by 10. This multiplication has a profound effect: it adds a new place value to the reversed number. Think of it like shifting the decimal point one position to the left.

reversed = reversed * 10 + digit

Iterative Process

The program then iterates through the following steps:

• num is divided by 10, leaving us with the remaining digits: 123.
• In the second iteration, digit equals 3, reversed becomes 4 * 10 + 3 = 43, and num is reduced to 12.
• The third iteration yields digit equal to 2, reversed becomes 43 * 10 + 2 = 432, and num dwindles to 1.
• The final iteration results in digit equal to 1, reversed becomes 432 * 10 + 1 = 4321, and num reaches 0.

The Grand Finale

When num finally reaches 0, the while loop exits, and the reversed variable proudly holds the reversed number: 4321.

while (num!= 0) {
    digit = num % 10
    reversed = reversed * 10 + digit
    num /= 10
}

Java Counterpart

Curious about the Java equivalent? Here’s the Java program to reverse a number, showcasing the same logic and principles:

int num = 1234;
int reversed = 0;
while (num!= 0) {
    int digit = num % 10;
    reversed = reversed * 10 + digit;
    num /= 10;
}
System.out.println("Reversed number: " + reversed);

Now, go ahead and try reversing numbers like a pro!